Question

To what temperature must Indian gas sample be heated to double its pressure if the initial volume of gas at 75 degree celsius is decreased by 15%?

Answer 1

According to gas law,

$PV=nRT$

Where n and R are constants

Therefore, we can write as,

$P_1\times \frac{V_1}{T_1}=P_2\times \frac{V_2}{T_2}$

Here,

$T_1=273+75=348K$

$P_2=2P_1$

$V_2=\frac{V_1-15V_1}{100}=0.85V_1$

$T_2=?$

$\frac{P_1\times V_1}{348}=2P_1\times \frac{0.85V_1}{T_2}$

$T_2=348\times 1.7=591.6K$

$T_2=591.5-273={318.6}^{0}C$