Question

To what temperature must a neon gas sample be heated to double its pressure if the initial volume of gas at ${75}^{0}C$ is decreased by 15.0% by cooling the gas?

• A. 592 K
• B. 492 K
• C. 542 K
• D. 642 K

Answer 1

Answer: (A)

592 K

The correct option is A.

We have,

Initial volume is $V_1$

Initial temprature is $T_1={75}^{0}C$

Initial pressure is $P_1$

So, final temprature is $T_2=273+75=348K$

$V_2=V_1-\frac{15}{100}{V}_1$

$=\frac{85V_1}{100}$

Applying the gas formula,

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\frac{P_1{V}_1}{348}=\frac{2P_1\times 85V_1}{T_2\times 100}$

$T_2=\frac{2\times 85\times 348}{100}$

$T_2=591.6K$