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Thermal Energy

A gas is cool...

Question

A gas is cooled and loses $50$ J of heat. The gas cantracts as it cools and work done on the system equal to $20$ J is exchanged with the surroundings hence, $Δ$ E is:

A

70

J

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B

- 30

J

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C

30

J

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D

- 70

J

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Solution

The correct option is B $- 30$ J
$Δ U$ = change in internal energy
Q = heat(it is negative when system releases heat)
W = workdone (workdone on the system taken as negative)
$Δ U = Q - W$
= -50 + 20
= - 30 joule
So option B is correct.

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