Question

A gas is filed in a rigid container at pressure$P^0$. If the mass of each molecule is halved

Keeping the total number of molecules same and their r.m.s

speed is doubled then find the new pressure.

Answer 1

$P=\frac{1}{3}Mn{c}^2$

where c$⟶$ RMS velocity

$P_o=\frac{1}{3}Mn{c}^2{P}^{\prime }=\frac{1}{3}\frac{M}{2}n\left(4c^2\right)\frac{P_o}{P^{\prime }}=\frac{1}{2}{P}^{\prime }=2P_o$