A gas is kept at 13 $^{0}$ C in a vessel. If the volume of the gas is kept constant and is heated, the pressure will be doubled to its initial pressure at a temperature

572 K

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286 K

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143 K

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73 K

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Solution

The correct option is A 572 K
PV = nRT
since n and R and V are constant
$P_{1} T_{2} = P_{2} T_{1}$
here $V_{1} = V_{2}$
and $T_{1} = 286$
and $P_{2} = 2 P_{1}$
and $T_{2} = ?$ (to be determined)
Putting all the values, we get $T_{2} = \frac{P_{2} T_{1}}{P_{1}} = \frac{2 P_{1} \times 286}{P_{1}} = 572 K$

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A gas is kept at 130C in a vessel. If the volume of the gas is kept constant and is heated, the pressure will be doubled to its initial pressure at a temperature

The correct option is A 572 KPV = nRTsince n and R and V are constantP1T2=P2T1here V1=V2and T1=286and P2=2P1and T2=? (to be determined)Putting all the values, we get T2=P2T1P1=2P1×286P1=572K

A gas is kept at 13 $^{0}$ C in a vessel. If the volume of the gas is kept constant and is heated, the pressure will be doubled to its initial pressure at a temperature