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Question

A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature (V0,T0) and the magnitude of the slope of V-T curve is m. Find the value of CP and CV.

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Solution

For an adiabatic process : TVγ1=K=constant
Differentiating, we get T(γ1)Vγ2dV+Vγ1dT=0
dVdT=V(γ1)T

Now dVdTVo,To=m

Vo(γ1)To=m γ1=VomTo OR γ=1+VomTo ........(1)

Cv=f2RTo=RToγ1 (f/2=(γ1)1)

Cv=RTo×VomTo=RVom

Also Cp=γCv=(1+VomTo)RTom

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