A gas obeys $P (V - b) = R T$ . Which of the following are correct about this gas?

Isochoric curves have slope

= \frac{R}{V - b}

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Isochoric curves have slope

= \frac{R}{P}

and intercept b

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For the gas compressibility factor

= 1 + \frac{P b}{R T}

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The attraction forces are overcome by repulsive forces

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Solution

The correct options are
B Isochoric curves have slope $= \frac{R}{V - b}$
C The attraction forces are overcome by repulsive forces
D For the gas compressibility factor $= 1 + \frac{P b}{R T}$
As we know,
Z (compressibility factor) $= P V / R T = 1 + P b / R T$ and as Z>1 so attraction forces are overcome by repulsive forces.
And according to a given gas equation,
P and T curve have slope $= \frac{R}{V - b}$ .

Hence, the correct options are $A$ , $C$ and $D$

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Similar questions

P (V - b) = R T

I .

I s o c h o r i c c u r v e s h a v e s l o p e = \frac{R}{V - b}

I I .

\frac{R}{P}

I I I .

F o r t h e g a s c o m p r e s s i b i l i t y f a c t o r = 1 + \frac{R b}{R T}

I V .

A gas obeys the equation of state P(V-b) = RT (The parameter b is constant). The slope for an isochore will be:

P (V - b) = R T

A gas obeys the equation of state P(V-b) = RT (The parameter b is constant). The slope for an isochore will be:

P (V_{m} - b) = R T .

{(\frac{δ Z}{δ P})}_{T} is \frac{x b}{R T} .

x

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