Question

A gas obeys the equation of state $P(V-b)=RT$ (The parameter b is a constant). The slope for an isochore will be:

• A. negative
• B. zero
• C. $\frac{R}{(V-b)}$
• D. $\frac{R}{P}$

Answer 1

The correct option is C $\frac{R}{(V-b)}$

By given equation,

$P(V-b)=RT$

$P=\frac{RT}{(V-b)}$

$P=\left(\frac{R}{V-b}\right)T$

For isochoric system, $V$ is constant so

$P=mT$

$y=mx$

$\therefore$ slope $=\frac{R}{V-b}$