A gas occupies 100mL at 50degree C at 1atm pressure.The gas is cooled at constant pressure so that volume is reduced to 50mL.What is the final temperature of the gas

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Solution

Given $V_{2} = 50, V_{1} = 100, T_{1} = 323, T_{2} = ?$
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\Rightarrow T_{2} = \frac{V_{2} \times T_{1}}{V_{1}} = \frac{50 \times 323}{100} = 161.5 K$
$\Rightarrow T_{2} = - 111.5 C$ .

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A gas occupies 100mL at 50degree C at 1atm pressure.The gas is cooled at constant pressure so that volume is reduced to 50mL.What is the final temperature of the gas

Given V2=50,V1=100,T1=323,T2=?V1T1=V2T2⇒T2=V2×T1V1=50×323100=161.5K⇒T2=−111.5C .

Given $V_{2} = 50, V_{1} = 100, T_{1} = 323, T_{2} = ?$
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\Rightarrow T_{2} = \frac{V_{2} \times T_{1}}{V_{1}} = \frac{50 \times 323}{100} = 161.5 K$
$\Rightarrow T_{2} = - 111.5 C$ .