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Question
A gas occupies 11 L at 0.80 atm. What is the pressure if volume becomes 15 L? [T= Constant]
A gas occupies 11 L at 0.80 atm. What is the pressure if volume becomes 15 L? [T= Constant]
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Solution
The correct option is A 0.587 atm
According to Boyle's law: P1V1 = P2V2
(11 L) (0.8 atm) = (P2) (15 L)
P2 = 0.587 atm
According to Boyle's law: P1V1 = P2V2
(11 L) (0.8 atm) = (P2) (15 L)
P2 = 0.587 atm
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