A gas occupies 3 litres at 0-C - What volume will it occupy at - 20-C pressure remaining constant-

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Standard IX

Chemistry

Charles's Law

A gas occupie...

Question

A gas occupies 3 litres at $0^{\circ} C$ . What volume will it occupy at - $20^{\circ} C$ pressure remaining constant?

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Solution

V is directly proportional to T
0 degree celsius = 273k=T1
-20 degree celsius=253k=T2

Charles Gas law:

$\frac{V 1}{T 1} = \frac{V 2}{T 2}$
$\frac{V 1}{T 1} \times T 2 = V 2$
$\frac{3 L}{290 K} \times 253 K = V 2$
V2=2.78 litres

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A gas occupies 3 litres at 0∘C . What volume will it occupy at - 20∘C pressure remaining constant?

V is directly proportional to T 0 degree celsius = 273k=T1 -20 degree celsius=253k=T2 Charles Gas law: V1T1=V2T2 V1T1×T2=V2 3L290K×253K=V2 V2=2.78 litres

A gas occupies 3 litres at $0^{\circ} C$ . What volume will it occupy at - $20^{\circ} C$ pressure remaining constant?

V is directly proportional to T
0 degree celsius = 273k=T1
-20 degree celsius=253k=T2

Charles Gas law:

$\frac{V 1}{T 1} = \frac{V 2}{T 2}$
$\frac{V 1}{T 1} \times T 2 = V 2$
$\frac{3 L}{290 K} \times 253 K = V 2$
V2=2.78 litres