A gas occupies 3 litres at 0-C- What volume will it occupy at -20-C- pressure remaining constant-

According to Charle's law V_1T_1 = V_2T_2 If V_1= 3L, T_1 = 0+273= 273 K , T_2 = 20+273 = 253K Then V_2= 3× 253273 = 2.78L #160; ...

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Standard IX

Chemistry

The Ideal Gas Equation

A gas occupie...

Question

A gas occupies 3 litres at $0^{\circ} C$ . What volume will it occupy at $- 20^{\circ} C$ , pressure remaining constant?

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Solution

According to Charle's law $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
If $V_{1} = 3 L, T_{1} = 0 + 273 = 273 K, T_{2} = - 20 + 273 = 253 K$
Then $V_{2} = \frac{3 \times 253}{273} = 2.78 L$

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A gas occupies 3 litres at 0∘C. What volume will it occupy at −20∘C, pressure remaining constant?

According to Charle's law V1T1=V2T2If V1=3L,T1=0+273=273K,T2=−20+273=253KThen V2=3×253273=2.78L

A gas occupies 3 litres at $0^{\circ} C$ . What volume will it occupy at $- 20^{\circ} C$ , pressure remaining constant?

According to Charle's law $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
If $V_{1} = 3 L, T_{1} = 0 + 273 = 273 K, T_{2} = - 20 + 273 = 253 K$
Then $V_{2} = \frac{3 \times 253}{273} = 2.78 L$