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Gay-Lussac's Law

A gas occupie...

Question

A gas occupies $56 L$ at 1 atm and $273 K$ . the number of moles of the gas present is:

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Solution

Volume occupied by 1 mole of the gas at STP = $22.4 L$
$56 L$ will be occupied by, $\frac{1}{22.4} \times 56 = 2.5 moles$

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