A gas occupies a volume of $250 c m^{3}$ at $745 t o r r$ and $25^{\circ} C$ . What additional pressure is required to reduce the gas volume to $200 c m^{3}$ at the same temperature?

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Solution

Using Boyle's law,
$P_{1} V_{1} = P_{2} V_{2}$
= $250 \times 745 = 200 \times P_{2}$
= $P_{2} = 931.25 t o r r$
Additional Pressure $= 931.25 - 745 = 186.25 t o r r$

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A gas occupies a volume of 250 cm3 at 745 torr and 25∘C. What additional pressure is required to reduce the gas volume to 200 cm3 at the same temperature?

Using Boyle's law,P1V1=P2V2=250×745=200×P2=P2=931.25 torrAdditional Pressure=931.25−745=186.25 torr

A gas occupies a volume of $250 c m^{3}$ at $745 t o r r$ and $25^{\circ} C$ . What additional pressure is required to reduce the gas volume to $200 c m^{3}$ at the same temperature?

Using Boyle's law,
$P_{1} V_{1} = P_{2} V_{2}$
= $250 \times 745 = 200 \times P_{2}$
= $P_{2} = 931.25 t o r r$
Additional Pressure $= 931.25 - 745 = 186.25 t o r r$