A gas of volume 2000ml is kept in a vessel at a pressure of 103 pascals at a temperature of 27- C- If the pressure is increased to 105 pascals at the same temperature- the volume of the gas becomes

P_1V_1=P_2V_2 P_1=10^3 pas, V_1=2000 ml P_2=10^5 pas, V_2=? 2000× 10^3=10^5× V_2 V_2=20 ml ...

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Standard XIII

Chemistry

Boyle's Law

A gas of volu...

Question

A gas of volume 2000ml is kept in a vessel at a pressure of $10^{3}$ pascals at a temperature of $27^{\circ} C$ . If the pressure is increased to $10^{5}$ pascals at the same temperature, the volume of the gas becomes

1000 ml

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20 ml

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2 ml

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200 ml

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Solution

The correct option is B
20 ml

$P_{1} V_{1} = P_{2} V_{2}$
$P_{1} = 10^{3} p a s, V_{1} = 2000 m l$
$P_{2} = 10^{5} p a s, V_{2} = ?$
$2000 \times 10^{3} = 10^{5} \times V_{2}$
$V_{2} = 20 m l$

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A gas of volume 2000ml is kept in a vessel at a pressure of 103 pascals at a temperature of 27∘ C. If the pressure is increased to 105 pascals at the same temperature, the volume of the gas becomes

The correct option is B 20 ml P1V1=P2V2 P1=103 pas, V1=2000ml P2=105 pas, V2=? 2000×103=105×V2 V2=20ml

A gas of volume 2000ml is kept in a vessel at a pressure of $10^{3}$ pascals at a temperature of $27^{\circ} C$ . If the pressure is increased to $10^{5}$ pascals at the same temperature, the volume of the gas becomes

The correct option is B
20 ml

$P_{1} V_{1} = P_{2} V_{2}$
$P_{1} = 10^{3} p a s, V_{1} = 2000 m l$
$P_{2} = 10^{5} p a s, V_{2} = ?$
$2000 \times 10^{3} = 10^{5} \times V_{2}$
$V_{2} = 20 m l$