A gas thermometer is used for measurement of temperature has a gas in a closed volume around a pressure of 120 psi at a temperature of $25^{\circ} C .$ What will be the pressure (PSL), if the temeprature is found to be $100^{\circ} C$ after some time?
150.186

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Solution

The correct option is A 150.186
The constant volume pressure is directly proportional to temperature i.e,

$P \propto T$

then

$\frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}}$

(Where T is in Kelvin.)

So for the given problem first convert the tempeature to Kelvin,

Hence,

$T_{1} = 25^{\circ} C o r 298 K$

$a n d T_{2} = 100^{\circ} C o r 373 K$

$P_{2} = \frac{T_{2}}{T_{1}} P_{1}$

$P_{2} = \frac{373}{298} \times 120 p s i$

$P_{2} = 150.20 p s i$

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