A gaseous alkane is exploded with oxygen. The volume of $O_{2}$ for complete combustion of alkane to $C O_{2}$ formed is in the ratio $7 : 4$ . The molecular formula of alkane is:

C_{2} H_{6}

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C_{3} H_{8}

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C_{4} H_{10}

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C H_{4}

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Solution

The correct option is B $C_{2} H_{6}$
The balanced reaction is given below:

$C_{n} H_{2 n + 2} + [n + \frac{n + 1}{2}] O_{2} \to n C O_{2} + (n + 1) H_{2} O$

Given,

$\frac{n + \frac{n + 1}{2}}{n} = \frac{7}{4} ⟹ n = 2$

Hence, the alkane is $C_{2} H_{6}$ .

Hence, the correct option is $A$

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Similar questions

Q. A gaseous alkane is exploded with oxygen. The moles of

O_{2}

for complete combustion and

C O_{2}

formed is in the ratio

7 : 4

. Deduce the molecular formula of alkane.

A gaseous alkane is burnt completely in oxygen. The volume of $O_{2}$ required for complete combustion to the volume of $C O_{2}$ formed is 7:4. Determine the formula for alkane. [Alkane is $C_{n} H_{2 n + 2}$ ]

Q. A gaseous alkane is exposed to oxygen. The volume of

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_____etc? Write the general formula of these compounds.

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A gaseous alkane is exploded with oxygen. The volume of O2 for complete combustion of alkane to CO2 formed is in the ratio 7:4. The molecular formula of alkane is:

The correct option is B C2H6The balanced reaction is given below:CnH2n+2+[n+n+12]O2→nCO2+(n+1)H2OGiven, n+n+12n=74⟹n=2Hence, the alkane is C2H6.Hence, the correct option is A

A gaseous alkane is exploded with oxygen. The volume of $O_{2}$ for complete combustion of alkane to $C O_{2}$ formed is in the ratio $7 : 4$ . The molecular formula of alkane is:

The correct option is B $C_{2} H_{6}$
The balanced reaction is given below:

$C_{n} H_{2 n + 2} + [n + \frac{n + 1}{2}] O_{2} \to n C O_{2} + (n + 1) H_{2} O$

Given,

$\frac{n + \frac{n + 1}{2}}{n} = \frac{7}{4} ⟹ n = 2$

Hence, the alkane is $C_{2} H_{6}$ .

Hence, the correct option is $A$