Question

A gaseous hydrocarbon weighs 0.70 g and contains 0.60 g of carbon. The molecular formula of the compound if its molecular weight is 70 is:

$(C=12,H=1)$

• A. $C_5{H}_{12}$
• B. $C_4{H}_8$
• C. $C_4{H}_{10}$
• D. $C_5{H}_{10}$

Answer 1

The correct option is D $C_5{H}_{10}$

Mass of carbon in one mole compound $=0.6\times \frac{70}{0.7}=60gm$
mass of H $=$10 gm. So compound is $C_5{H}_{10}$