A gaseous mixture conatins $10^{22}$ molecules of hydrogen and $10^{21}$ molecules of oxygen. calculate the total mass of gaseous sample.

Open in App

Solution

A gaseous mixture conatins $10^{22}$ molecules of hydrogen and $10^{21}$ molecules of oxygen.
1 mole of any substance contains Avogadro's number $(6.023 \times 10^{23})$ of molecules and its weight is equal to molecular weight. The molecular weights of hydrogen and oxygen are 2 g/mol and 32 g/mol respectively.
Weight of hydrogen $= \frac{10^{22} m o l e c u l e s \times 2 g / m o l}{6.023 \times 10^{23} m o l e c u l e s / m o l} = 0.0332 g$
Weight of oxygen $= \frac{10^{21} m o l e c u l e s \times 32 g / m o l}{6.023 \times 10^{23} m o l e c u l e s / m o l} = 0.053 g$
Total mass of gaseous sample $= 0.0332 + 0.053 = 0.086 g$

Suggest Corrections

Similar questions

Q. The total number of moles present in a gaseous mixture containing

8

g of oxygen,

11.2

L of

C O_{2}

and

3 \times

10^{22}

molecules of

N_{2}

at STP is:

The total number of moles present in a gaseous mixture containing $8 g$ of oxygen, $11.2 l i t r e s$ of $C O_{2}$ and $3 \times 10^{22}$ molecules of $N_{2}$ at STP is

Q. The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is

1 : 4

. Their ratio of number of molecules is:

Q. A gaseous mixture contains oxygen and nitrogen in the ratio of 1 :4 by mass. Therefore, the ratio of their number of molecules is:

Q. In a gaseous mixture at 4 atm pressure, 25% of molecules are Nitrogen, 40% of molecules are carbon dioxide and the rest are oxygen. The partial pressure of oxygen in the mixture is:

Join BYJU'S Learning Program

A gaseous mixture conatins 1022 molecules of hydrogen and 1021 molecules of oxygen. calculate the total mass of gaseous sample.

A gaseous mixture conatins $10^{22}$ molecules of hydrogen and $10^{21}$ molecules of oxygen. calculate the total mass of gaseous sample.