Question

A gaseous mixture containing ${0.35}_g$ of $N_2$ and 5600 ml of $O_2$ at STP has kept in a 5 liters at 300K. The total temperature of the gaseous mixture is?

• A. 1.293 atm
• B. 1.2315 atm
• C. 12.315 atm
• D. 0.616 atm

Answer 1

Answer: (A)

1.293 atm

Moles of $O_2=\frac{5600}{22400}=0.25=n_{O_2}$

Moles of $N_2=\frac{0.35}{28}=0.0125=n_{N_2}$

Initial pressure of $N_2=\frac{n_{N_2}RT}{V}=\frac{0.0125\times 0.0821\times 300}{5}=0.061atm$

Potential pressure of $O_2=\frac{n_{O_2}RT}{V}=\frac{0.25\times 0.0821\times 300}{5}=1.231atm$

$\therefore$ Total pressure $=1.231+0.061=1.292atm$