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Standard XII

Chemistry

Concentration Terms

A gaseous mix...

Question

A gaseous mixture contains $4.0$ gm of $H_{2}$ and $56.0$ gm of $N_{2}$ . The mole fraction of $H_{2}$ in the mixture is:

0.5

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Solution

The correct option is A $0.5$
$X_{H_{2}} = \frac{n_{H_{2}}}{n}$

moles of $H_{2} = \frac{4}{2} = 2$

moles of $N_{2} = \frac{56}{28} = 2$

Total moles of mixture $=$ 4

$Mole fraction of solute, χ=Moles of soluteMoles of solute+Moles of solvent$

Mole fraction of $H_{2} = \frac{2}{4} = 0.5$

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A gaseous mixture contains 4.0 gm of H2 and 56.0 gm of N2. The mole fraction of H2 in the mixture is:

The correct option is A 0.5XH2=nH2nmoles of H2=42=2moles of N2=5628=2Total moles of mixture = 4Mole fraction of solute, χ=Moles of soluteMoles of solute+Moles of solventMole fraction of H2=24=0.5

A gaseous mixture contains $4.0$ gm of $H_{2}$ and $56.0$ gm of $N_{2}$ . The mole fraction of $H_{2}$ in the mixture is:

The correct option is A $0.5$
$X_{H_{2}} = \frac{n_{H_{2}}}{n}$

moles of $H_{2} = \frac{4}{2} = 2$

moles of $N_{2} = \frac{56}{28} = 2$

Total moles of mixture $=$ 4

$Mole fraction of solute, χ=Moles of soluteMoles of solute+Moles of solvent$

Mole fraction of $H_{2} = \frac{2}{4} = 0.5$