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Dalton's Law of Partial Pressures

A gaseous mix...

Question

A gaseous mixture of three gases A, B and C has a pressure of 10atm. The total number of moles of all gases is 10. The partial pressure of A and B are 3 and 1 atm respectively. If C has a molecular weight of 2, then find the weight of C in grams present in the mixture.

A

6

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B

3

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C

12

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D

8

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Solution

The correct option is C
12

n = 10

p = 10

$p_{c}$ = 6

6 = $\frac{w}{M_{c}}$

6 = $\frac{w}{2}$

$W_{c} = 12 g m$

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