Question

A gaseous oxide contains 30.4% of nitrogen, one molecule of which contains one nitrogen atom. The density of the oxide relative to oxygen is

• A. 0.94
• B. 1.44
• C. 1.50
• D. 3.0

Answer 1

The correct option is B

1.44

$\frac{d_{oxide}}{d_{(}{O}_2)}$=$\frac{M{W}_{oxide}}{M_{(}{O}_2)}$+ $\frac{M_{oxide}}{32}$

100gm of oxide contains 30.4 Nitrogen

$\frac{100}{30.4}$gm of oxide contains 1gm nitrogen

$\frac{100}{30.4}$$\times$14gm of oxide contains 14 gm Nitrogen

$M_{oxide}$=$\frac{14\times {100}^{\circ }}{30.4}$

$\frac{d_{oxide}}{d_{(}{O}_2)}$ =$\frac{1400}{30}.\frac{4}{32}$ = 1.44