Hydrogen combines with nitrogen in a 3:14 weight ratio to form ammonia. If every molecule of ammonia contains three atoms of hydrogen and one atom of nitrogen, an atom of nitrogen must weigh :

14 times the mass of a hydrogen atom

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14/3 times the mass of a hydrogen atom

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3 times the mass of a hydrogen atom

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3/14 times the mass of a hydrogen atom

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Solution

The correct option is A 14 times the mass of a hydrogen atom
In ammonia, nitrogen and hydrogen are always present in the ratio 14:3 by mass

Let's assume mass of a Nitrogen atom is $X$ and that of a Hydrogen atom is $Y$ .

From the law of constant proportion,

$3 Y : X = 3 : 14 \Rightarrow X = 14 \times Y$

Mass of a Nitrogen atom $(X)$ is 14 times that of a Hydrogen atom ( $Y$ ).

Hence Option A is correct.

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