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Question
Hydrogen combines with oxygen in a 1:8 weight ratio to form water. If every molecule of water contains two atoms of hydrogen and one atom of oxygen, an atom of oxygen must weigh:
Hydrogen combines with oxygen in a 1:8 weight ratio to form water. If every molecule of water contains two atoms of hydrogen and one atom of oxygen, an atom of oxygen must weigh:
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Solution
The correct option is B 16 times the mass of a hydrogen atom
The ratio of the mass of hydrogen to the mass of oxygen is always 1:8.
Let's assume the mass of an Oxygen atom is X u and that of a Hydrogen atom is Y u.
From the law of constant proportion,
2Y:X=1:8⇒X=16×Y
The mass of an Oxygen atom (X) is 16 times that of a Hydrogen atom (Y).
Hence Option B is correct.
The ratio of the mass of hydrogen to the mass of oxygen is always 1:8.
Let's assume the mass of an Oxygen atom is X u and that of a Hydrogen atom is Y u.
From the law of constant proportion,
2Y:X=1:8⇒X=16×Y
The mass of an Oxygen atom (X) is 16 times that of a Hydrogen atom (Y).
Hence Option B is correct.
From the law of constant proportion,
2Y:X=1:8⇒X=16×Y
The mass of an Oxygen atom (X) is 16 times that of a Hydrogen atom (Y).
Hence Option B is correct.
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(b) 
(c) 