Question 98

A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.

Open in App

Solution

Let x be the age of the girl.
Then, age of her father = (x + 28) years
According to the question,
x + (x + 28) = 50
$\Rightarrow 2 x + 28 = 50 \Rightarrow 2 x = 50 - 28 \Rightarrow 2 x = 22 \Rightarrow x = \frac{22}{2} = 11 y e a r s$
Hence, the age of the girls is 11 years and the age of her father's age is (11 + 28), i.e. 39 years.

Suggest Corrections

125

Similar questions

A girl is 28 years younger than her father. sum of their ages is 50 years find the ages of the girl and father.

Q. The difference in age between a girl and her younger sister is 4 years. The younger sister in turn is 4 years older than her brother. The sum of the ages of the younger sister and her brother is 16. How old are the three children?

While having food Ray asked Tanu to tell him more about her. Tanu decided to first tell about her father as she was a daddy's girl. Ray asked her what her father's age was. Tanu told that five years ago the age of her father was twice her age. The sum of their present ages is 40 years. Tanu asked Ray to tell their present ages. The present age of Tanu and her father is :

Q. Rene ages is 6 years older than her younger sister. After 10 years the sum their ages will be 50 years. Find their present ages .

Question 87

Let Kanika's present age be x years. Complete the following table, showing ages of her ralatives.

$\begin{matrix} S i t u a t i o n (d e s c r i b e d i n o r d i n a r y l a n g u a g e) & E x p r e s s i o n (i) & H e r b r o t h e r i s 2 y e a r s y o u n g e r . & - - - (i i) & H e r f a t h e r^{'} s a g e e x c e e d s h e r a g e b y 35 y e a r s . & - - - (i i i) & M o t h e r^{'} s a g e i s 3 y e a r s l e s s t h a n t h a t o f h e r f a t h e r . & - - - (i v) & H e r g r a n d f a t h e r^{'} s a g e i s 8 t i m e s o f h e r a g e . & - - - \end{matrix}$

Join BYJU'S Learning Program

Explore more

Applications (Word Problem)

Standard VII Mathematics

Join BYJU'S Learning Program

Question 98 A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.

Let x be the age of the girl. Then, age of her father = (x + 28) years According to the question, x + (x + 28) = 50 ⇒2x+28=50⇒2x=50−28⇒2x=22⇒x=222=11 years Hence, the age of the girls is 11 years and the age of her father's age is (11 + 28), i.e. 39 years.

Question 98

A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.