Question

Rene ages is 6 years older than her younger sister. After 10 years the sum their ages will be 50 years. Find their present ages .

Answer 1

Let's have R be Rene's age.

R


And we have a younger sister who is 6 years younger than Rene:

R−6


In 10 years, the sum of their ages will be 50. So in 10 years Rene will be:

R+10


and her sister will be

R−6+10


and the two added together will be 50:

(R+10)+(R−6+10)=50


How old are they now?
(R+10)+(R−6+10)=50


2R+14=50


2R=36


R=18


and her sister is

R−6=18−6=12

Rene is 18 years now and her younger sister is 12 years now.