Question 98

A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.

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Solution

Let x be the age of the girl.
Then, age of her father = (x + 28) years
According to the question,
x + (x + 28) = 50
$\Rightarrow 2 x + 28 = 50 \Rightarrow 2 x = 50 - 28 \Rightarrow 2 x = 22 \Rightarrow x = \frac{22}{2} = 11 y e a r s$
Hence, the age of the girls is 11 years and the age of her father's age is (11 + 28), i.e. 39 years.

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Standard VII Mathematics

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Question 98 A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.

Let x be the age of the girl. Then, age of her father = (x + 28) years According to the question, x + (x + 28) = 50 ⇒2x+28=50⇒2x=50−28⇒2x=22⇒x=222=11 years Hence, the age of the girls is 11 years and the age of her father's age is (11 + 28), i.e. 39 years.

Question 98

A girl is 28 years younger than her father. The sum of their ages is 50 years. Find the ages of the girl and her father.