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Question

(a) Give a possible explanation for each one of the following:
(i) There are two NH2, groups in semicarbazide. However, only one such group is involved in the formation of semicarbazones.
(ii) Cyclohexanone forms cyanohydrin in good yield but 2, 4, 6-trimethylcyclohexanone does not.
(b) An organic compound with molecular formula C9H10O forms 2, 4, -DNP derivative, reduces Tollens' reagent and undergoes Cannizzaro's reaction. On vigorous oxidation it gives 1, 2-benzene-di-carboxylic acid. Identify the compound?

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Solution

(a) (i) Semicarbazide undergoes resonance involving only one of the two-NH 2 groups, which is attached directly to the carbonyl carbon atom.
Therefore, the electron density on NH2 group involved in the resonance also decreases.
As a result, it cannot act as a nucleophile. Since the other NH2 group is not involved in resonance, it can act as a nucleophile and can attack carbonyl carbon atoms of aldehydes and ketones to produce semicarbazones.
(ii) Cyclohexanone form cyanohydrins according to the following equation.
In this case, the nucleophile CN can attack without any steric hindrance. However, in the case of 2, 4, 6-trimethylcyclohexanone, methyl groups at ± -position offer steric hindrances and as a result, CN cannot attack effectively.
For this reason, it does not form a cyanohydrin.
(b) It is given that the compound (with molecular formula C9H10O forms 2, 4-DNP derivative and reduces and Tollen's reagent. Therefore, the given compound must be an aldehyde.
Again, the compound undergoes Cannizzaro reaction and on oxidation gives 1, 2-benzenedicarboxylic acid. Therefore, the CHO group is directly attached to a benzene ring and this benzaldehyde is ortho-substituted. Hence, the compound is 2-ethylbenzaldehyde
The given reaction can be explained by the following equations.

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