(a) (i) Semicarbazide undergoes resonance involving only one of the two-NH 2 groups, which is attached directly to the carbonyl carbon atom.
Therefore, the electron density on −NH2 group involved in the resonance also decreases.
As a result, it cannot act as a nucleophile. Since the other −NH2 group is not involved in resonance, it can act as a nucleophile and can attack carbonyl carbon atoms of aldehydes and ketones to produce semicarbazones.
(ii) Cyclohexanone form cyanohydrins according to the following equation.
In this case, the nucleophile CN− can attack without any steric hindrance. However, in the case of 2, 4, 6-trimethylcyclohexanone, methyl groups at ∈± -position offer steric hindrances and as a result, CN− cannot attack effectively.
For this reason, it does not form a cyanohydrin.
(b) It is given that the compound (with molecular formula C9H10O forms 2, 4-DNP derivative and reduces and Tollen's reagent. Therefore, the given compound must be an aldehyde.
Again, the compound undergoes Cannizzaro reaction and on oxidation gives 1, 2-benzenedicarboxylic acid. Therefore, the −CHO group is directly attached to a benzene ring and this benzaldehyde is ortho-substituted. Hence, the compound is 2-ethylbenzaldehyde
The given reaction can be explained by the following equations.