A given amount of a gas is heated till the volume and pressure both increase by $2 %$ each the percentage change in temperature of the gas is equal to nearly

2 %

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3 %

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4 %

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1 %

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Solution

The correct option is C $4 %$
$\frac{d P}{P} + \frac{d V}{V} = \frac{d T}{T} N o w d P = 0.02 P, d V = 0.02 V 0.02 + 0.02 = \frac{d T}{T} \frac{d T}{T} \times 100 = 4$

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