Question

A given weak acid (0.01M) has pKa = 6. The pH of the solution is:

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

The correct option is B 4

$pH=\frac{1}{2}pKa-\frac{1}{2}logC=\frac{1}{2}\times 6-\frac{1}{2}log\left(0.01\right)$
= 3 + 1 = 4.