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Salt of Weak Acid and Strong Base

pH of 0.01 M ...

Question

pH of 0.01 M solution of HA is 4. Find the value of pKa of HA at $25^{\circ} C$

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Solution

$p H = 4; [H^{+}] = 10^{- 4}$
$C = 10^{- 2}; [H^{+}] = \sqrt{K a . C}$
$\Rightarrow 10^{- 4} = \sqrt{K a . 10^{- 2}}$
$\Rightarrow K a = 10^{- 6}$
so, $p K_{a} = - l o g (K_{a})$
$\Rightarrow p K a = 6$

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