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Question

The pH of a 0.01M HCN solution for which pKa is 4 is:

A
0.47
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B
1.2
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C
3.0
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D
4.0
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Solution

The correct option is D 3.0
Given, pKa=4

Ka=1×104

[H+]=Ka.C=1×104×0.01

=106=103M

pH=log[H+]=log(103)=3

Option C is correct.

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