(A) gives white ppt with AgNO3 soluble in aq NH3. (A) gives green ppt (B) with NaOH but ppt dissolves to yellow solution (C) when heated with H2O2. (C) gives yellow ppt (D) with BaCl2. According to above experiment complete the matrix.
Open in App
Solution
The compound (A) is CrCl3. It gives white ppt of AgCl with AgNO3 which is soluble in aq NH3. CrCl3+3AgNO3→3AgCl↓(whiteppt)+Cr(NO3)3 AgCl+2NH3→[Ag(NH3)2]Cl (A) gives green ppt (B) of Cr(OH)3 with NaOH but ppt dissolves to yellow solution (C) of Na2CrO4 when heated with H2O2. CrCl3+3NaOH→Cr(OH)3↓(greenppt)+3NaCl Cr(OH)3H2O2−−−−→NaOHNa2CrO4(yellowsolution) The compound (C) (Na2CrO4) gives yellow ppt (D) of BaCrO4 with BaCl2. Na2CrO4+BaCl2→BaCrO4+2NaCl