Question

# A glass flask of volume 200 cm3 is just filled with mercury at 20∘C. The amount of mercury that will overflow when the temperature of the system is raised to 100∘C is (γglass=1.2×10−5 ∘C−1,γmercury=1.8×10−4 ∘C−1)

A
2.15 cm3
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B
2.69 cm3
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C
2.52 cm3
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D
2.25 cm3
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Solution

## The correct option is B 2.69 cm3Due to increase in the temperature, both the mercury and the glass vessel will expand Increase in the volume of mercury =VγmercuryΔT =(200)×1.8×10−4×(100−20) =2.88 cm3 Increase in the volume of glass =VγglassΔT =(200)×1.2×10−5×(100−20) =0.192 cm3. So, the amount as mercury that will overflow =(2.880−0.192)=2.688=2.69 cm3 Hence, option (B) is correct. Volume of overflow =VΔT(γmercury−γglass)

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