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Question

A glass flask of volume 200 cm3 is just filled with mercury at 20C. The amount of mercury that will overflow when the temperature of the system is raised to 100C is

(γglass=1.2×105 C1,γmercury=1.8×104 C1)

A
2.15 cm3
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B
2.69 cm3
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C
2.52 cm3
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D
2.25 cm3
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Solution

The correct option is B 2.69 cm3
Due to increase in the temperature, both the mercury and the glass vessel will expand

Increase in the volume of mercury

=VγmercuryΔT

=(200)×1.8×104×(10020)

=2.88 cm3

Increase in the volume of glass

=VγglassΔT

=(200)×1.2×105×(10020)

=0.192 cm3.

So, the amount as mercury that will overflow
=(2.8800.192)=2.688=2.69 cm3

Hence, option (B) is correct.
Volume of overflow =VΔT(γmercuryγglass)

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