A glass plate 0.6 micron thickness is illuminated by a beam of white light of wavelength $λ$ normal to the plane. $λ$ is in the range of 400 $n m$ and 750 $n m$ . Refractive index of glass is 1.5. Wavelengths that get intensified in the reflected beam are

400 n m

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460 n m

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514.2 n m

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720 n m

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Solution

The correct options are
A $400 n m$
C $514.2 n m$
D $720 n m$

The phase difference due to reflection is $π$ . Therefore, for bright reflected light, the phase difference due to the path difference should be $π$ . Therefore,
$2 μ t = (2 n - 1) \frac{λ}{2}$

$λ = \frac{4 μ t}{(2 n - 1)} = \frac{4 \times 3 \times 0.6 \times 10^{- 6}}{2 \times (2 n - 1)} = \frac{3.6 \times 10^{- 6}}{(2 n - 1)}$

$λ = \frac{3600}{(2 n - 1)} n m$

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A glass plate 0.6 micron thickness is illuminated by a beam of white light of wavelength λ normal to the plane. λ is in the range of 400 nm and 750 nm. Refractive index of glass is 1.5. Wavelengths that get intensified in the reflected beam are

A glass plate 0.6 micron thickness is illuminated by a beam of white light of wavelength $λ$ normal to the plane. $λ$ is in the range of 400 $n m$ and 750 $n m$ . Refractive index of glass is 1.5. Wavelengths that get intensified in the reflected beam are