A glass tube of volume 112 ml containing a gas is partially evacuated till the pressure in it drops to 3.8×10−5 torr at 00C. The number of molecules of the gas remaining in the tube is
A
3.7×1017
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B
1.5×1014
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C
4.5×1018
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D
1.5×1019
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Solution
The correct option is B1.5×1014 PV=nRT n=PVRT=3.8×10−5×112×10−362.4×273 =0.02461×10−8mol
No. of molecules = 0.02461×10−8mol =1.5×1014