Question

A gobar gas plant produces methane and supplies and supplies to the families. If a family requires $15,000kJ$ of energy per day, how many days will the quota of $10kg$ will last?

$({\Delta }_{c}H$ of $C{H}_4=-1665kJmo{l}^{-1})$

Answer 1

Weight of methane $=10kg$

moles $=\frac{10000}{\text{m.m of methane}}=\frac{10000}{16}$

${\Delta }_{c}H$ of $C{H}_4=-1665KJ/mol$

Total energy released by turning 10 kg of methane $=1665KJ/ml\times \frac{10000}{16}mol$

$=\frac{16650000}{16}KJ$

No. of Days $=\frac{16650000}{16\times 150000}=\frac{1110}{16}=69.3$

$\simeq 69$ days