Question

A graph of concentration versus time data for a second-order reaction gives a straight line in which of the following plots of the data?

• A. $[A{]}_t=-kt+[A{]}_0$
• B. $ln[A{]}_t=-kt+ln[A{]}_0$
• C. $\frac{1}{\left[A_t\right]}=kt+\frac{1}{\left[A_0\right]}$
• D. All of the above
• E. None of the above

Answer 1

The correct option is A $[A{]}_t=-kt+[A{]}_0$

Let the concentration at $t=0$ be $\left[A_o\right]$ & at $t=t$ be $\left[A_t\right]$

By graph,

$\left[A_t\right]=Kt+\left[A_o\right]$

For negative slop,

$\left[A_t\right]=-Kt+\left[A_o\right]$