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Standard XII

Chemistry

Elementary and Complex Reactions

Consider the ...

Question

Consider the following case of completing first order reactions.

After the start of the reaction at t = 0 with only A, the [B] is equal to the [C] at all times. The time in which all three concentrations will be equal is given by

$t = \frac{1}{3 K_{1}} l n 2$

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$t = \frac{1}{3 K_{1}} l n 3$

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$t = \frac{1}{3 K_{2}} l n 2$

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$t = \frac{1}{2 K_{2}} l n 3$

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Solution

The correct option is D
$t = \frac{1}{2 K_{2}} l n 3$

$K_{1} = K_{2} = \frac{2}{3} r d$ of A has reacted for [A] = [B] = [C]

$∴ K_{1} + K_{2} = \frac{1}{t} l n \frac{[A]_{0}}{\frac{1}{3} [A]_{0}}$

$t = \frac{1}{K_{1} + K_{2}} l n 3 = \frac{1}{2 K_{1}} l n 3 = \frac{1}{2 K_{2}} l n 3$

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Consider the following case of completing first order reactions. After the start of the reaction at t = 0 with only A, the [B] is equal to the [C] at all times. The time in which all three concentrations will be equal is given by

The correct option is D t=12K2ln3 K1=K2=23rd of A has reacted for [A] = [B] = [C] ∴K1+K2=1tln[A]013[A]0 t=1K1+K2ln3=12K1ln3=12K2ln3

Consider the following case of completing first order reactions.

After the start of the reaction at t = 0 with only A, the [B] is equal to the [C] at all times. The time in which all three concentrations will be equal is given by

The correct option is D
$t = \frac{1}{2 K_{2}} l n 3$

$K_{1} = K_{2} = \frac{2}{3} r d$ of A has reacted for [A] = [B] = [C]

$∴ K_{1} + K_{2} = \frac{1}{t} l n \frac{[A]_{0}}{\frac{1}{3} [A]_{0}}$

$t = \frac{1}{K_{1} + K_{2}} l n 3 = \frac{1}{2 K_{1}} l n 3 = \frac{1}{2 K_{2}} l n 3$