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Question

A green colored water soluble substance, (A), forms a greenish precipitate (B) with NH4OH in presence of NH4Cl (excess). When (B) is oxidized with a little sodium bismuthate in presence of H2SO4, a orange solution is obtained. If now a little solid Na2O2 is added, an intensely blue-colored compound is formed, extractable with ether. (A) yields a bulky white precipitate with BaCl2 solution. Suggest the nature of the compound (A):

A
Nickel (II) sulphate
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B
Copper (II) sulphate
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C
Chromium (III) sulphate
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D
Ferrous sulphate
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Solution

The correct option is C Chromium (III) sulphate
Compound (A) is chromium (III) sulphate Cr2(SO4)3.
It is green coloured and water soluble. In presence of excess NH4Cl, it reacts with NH4OH to form green precipitate of chromium (III) hydroxide Cr(OH)3
When chromium (III) hydroxide is oxidized with a little sodium bismuthate in presence of H2SO4, a orange solution is obtained. If now a little solid Na2O2 is added, an intensely blue-colored compound is formed, extractable with ether.
Chromium (III) sulphate yields a bulky white precipitate of barium sulphate BaSO4 with BaCl2 solution.
Cr2(SO4)3+3BaCl23BaSO4+2CrCl3

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