Question

A group of 48 workers can complete a piece of work in 11 days. But 48 workers worked on first day, 44 workers worked on second day, 40 workers worked on third day and so on. Unfortunately, on the 10th day, they had to restart the entire work . Then, find the time taken by the remaining workers to complete the entire work.

• A. 40 days
• B. 44 days
• C. 48 days
• D. 68 days

Answer 1

The correct option is B

44 days

Number of workers left on 10th day
= 48 + (10 - 1)(-4)
[$\because$ a = 48, d = -4]
= 48 + 9 $\times$ (-4)
= 48 - 36 = 12
Now, work done by 48 workers in 1 day $=\frac{1}{11}$
$\therefore$ Work done by 1 worker in 1 day $=\frac{1}{11\times 48}$
$\therefore$ Work done by 12 workers in 1 day $=\frac{12}{11\times 48}=\frac{1}{44}$
Then, time taken by the remaining workers to complete the entire work, is 44 days.