Question

A group of 48 workers can complete a piece of work in 11 days. But 48 workers worked on first day, 44 workers worked on second day, 40 workers worked on third day and so on. Unfortunately, on the 10th day, all the work got ruined. Then, find the time taken by the workers left on 10th day to complete the entire work.

• A. 40 days
• B. 41 days
• C. Can't be determined
• D. None of the above

Answer 1

The correct option is D None of the above

Number of workers left on 10th day
= 48 + (10 - 1)(-4)
[$\because$ a = 48, d = -4]
= 48 + 9 $\times$ (-4)
= 48 - 36 = 12
Now, work done by 48 workers in 1 day $=\frac{1}{11}$
$\therefore$ Work done by 1 worker in 1 day $=\frac{1}{11\times 48}$
$\therefore$ Work done by 12 worker in 1 day $=\frac{12}{11\times 48}=\frac{1}{44}$
Then, time taken by the workers left, to complete the entire work, is 44 days.