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Series Combination of Cells

A group of N ...

Question

A group of N cells whose emf varies directly with the internal resistance as per the equation $E_{N} = 1.5 r_{N}$ are connected as shown in the following figure. The current i in the circuit is

0.51 amp

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5.1 amp

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0.15 amp

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1.5 amp

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Solution

The correct option is D 1.5 amp
$i = \frac{E_{e q}}{r_{e q}} = \frac{1.5 r_{1} + 1.5 r_{2} + 1.5 r_{3} + . . . . . .}{r_{1} + r_{2} + r_{3} + . . . . . .} = 1.5$ amp.

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E_{N} = 1.5 r_{N}

E_{N} = 1.5 r_{N}

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E_{N} = 1.5 r_{N}

I

E_{n}

r_{N}

E_{N} = 1.5 r_{N}

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