Question

A group of N cells whose emf varies directly with the internal resistance as per the equation $E_N=1.5r_N$ are connected as shown in the figure. The current I in the circuit is :-

• A. 5.1 A
• B. 0.51 A
• C. 1.5 A
• D. 0.15 A

Answer 1

The correct option is C 1.5 A

If the current I flows in anticlockwise direction,
$I=\frac{E_1+E_2+.......+E_N}{r_1+r_2+......+r_N}=\frac{1.5r_1+1.5r_2+.....+1.5r_N}{r_1+r_2+......+r_N}=1.5A$