Question

A gun is fitted on platform moving with velocity $\overrightarrow{V_1}=10\hat{i}m/s$. A bullet is fired from the gun with velocity $\overrightarrow{V_2}=(40\hat{i}+20\hat{j})m/s$ with respect to the platform. Then the horizontal range of projectile is

• A. 100 m
• B. 400 m
• C. 200 m
• D. 300 m

Answer 1

The correct option is C 200 m

The horizontal velocity of the particle in ground frame will be $u_x=10+40=50m/s$

initial vertical velocity in ground frame will be $u_y=20+0=20m/s$

so time of light will be $T=\frac{2u_y}{g}=\frac{2\times 20}{10}=4sec$

the horizontal distance covered in this interval or the $range$ will be

$R=u_x\times T=50\times 4=200meter$