A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per $m^{2}$ . Find the total cost of carpeting the hall.

₹ 224

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₹ 264

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₹ 642

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₹ 292

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Solution

The correct option is A
₹ 224

Area of parallelogram = Base $\times$ corresponding height

Area of parallelogram = 8 $\times$ (1.75 $\times$ 8)

Area of parallelogram = 112 $m^{2}$ .

Total cost of carpeting the hall = Cost per $m^{2}$ $\times$ Area

= ₹ 2/ $m^{2}$ $\times$ 112 $m^{2}$ = ₹ 224.

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Q. A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per

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, find the total cost of carpeting the hall.

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per $m^{2}$ . Find the total cost of carpeting the hall.

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ . Find the total cost of carpeting the hall.

A school has a hall $22 m$ long and $15.5 m$ wide , a carpet is laid inside the hall leaving around margin of $75 c m$ from the walls. Find area of carpet and area of strip uncovered . If width of carpet is $82 c m$ find its cost for $R s . 60$ per meter.

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A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per m2 . Find the total cost of carpeting the hall.

The correct option is A ₹ 224 Area of parallelogram = Base × corresponding height Area of parallelogram = 8 × (1.75 × 8) Area of parallelogram = 112 m2 ​. Total cost of carpeting the hall = Cost per m2 ×​ Area = ₹ 2/m2 × 112 m2 = ₹ 224.

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per $m^{2}$ . Find the total cost of carpeting the hall.