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Question

A hammer of mass 1 kg moving with a speed of 6 m/s strikes a wall and comes to rest in 0.1sec. Calculate :
1. An impulse of the force.
2. An average retarding force that stops the hammer.
3. Average retardation of the hammer.

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Solution

Mass of the hammer=1kg
Initial velocity(u)=6ms1
Final velocity(v)=0ms1

Tie taken(t)=0.1sec

(i)

impluse=m(vu)=1×(06)

=>6ms1

(ii)

a retarding force that stops a hammer

i.e.,
f=implusetime=60.1

=>60N

(iii)

retarding of the hammer
i.e.,

a=fm=601=60ms2

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