Question

A hammer of mass 1 kg was falling from a height of 1 m. It hits a nail and the nail penetrate a distance of 2 cm in a wooden block. Find out the impulse imparted by hammer on the nail if the collision takes 0.01 seconds. What is the average resisting force applied by wooden block on the nail. Is it equal to the force acting on the nail by the hammer ?

Answer 1

Dear Student,
$$\begin{gathered} impulseimpertedbyhammeronthenail=\frac{∆mv}{∆t}=\frac{\sqrt{2\times 10\times 1}\times 1-0\times 1}{.01}=\sqrt{2\times 10\times 1}\times 100N=447.2N \\ andworkdoneinpenetratingnail2cm=workdonebygravityinfallinghammerfrom1mheight=mgh=10J \\ soaveregeforceinpenetration=\frac{10}{2\times {10}^{-2}}=500N \end{gathered}$$
Regard