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Question

A hammer of mass M strikes a nail of mass m with velocity of u ms−1 and drives it a metres into a fixed block of wood. The average resistance of the wood to the penetration of the nail is:

A
(MM+m)u22a
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B
(M(M+m)2)u22a
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C
(M+mM)u22a
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D
(M2M+m)u22a
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Solution

The correct option is D (M2M+m)u22a
Using conservation of momentum we have
v=MuM+m ,
Thus we get
FS=12(M+m)v2
Fa=12(M+m)v2
F=12a(M+m)(MuM+m)2=(M2M+m)u22a

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